How to Balance Redox Reactions - Balancing Redox Reactions

10 I^- --> 5 I₂ + 10 e^-

16 H⁺ + 2 MnO₄^- + 10 e^- --> 2 Mn²⁺ + 8 H₂O

This yields the following final equation:

10 I^- + 10 e^- + 16 H⁺ + 2 MnO₄^- --> 5 I₂ + 2 Mn²⁺ + 10 e^- + 8 H₂O

Get the overall equation by canceling out the electrons and H₂O, H⁺, and OH^- that may appear on both sides of the equation:

10 I^- + 16 H⁺ + 2 MnO₄^- --> 5 I₂ + 2 Mn²⁺ + 8 H₂O

Index: How to Balance Redox Reactions - Balancing Redox Reactions

1. Balancing Redox Reactions - Half-Reaction Method
2. Balancing Redox Reactions - Separate the Reactions
3. Balancing Redox Reactions - Balance the Atoms
4. Balancing Redox Reactions - Balance the Charge
5. Balancing Redox Reactions - Add the Half-Reactions
6. Balancing Redox Reactions - Check Your Work